11*11的数独。每行每列的和等于671.
用IDA打开，先看看流程。
流程：
.text:01141F4A call dword_1152250+20h
.text:01141F50 retn
dword_1152250[0] = (int)func_hehe_sub_20_1141150;
dword_1152250[1] = (int)func_hehe_equ_0_1141180;
dword_1152250[2] = (int)func_hehe_equ_fu3_11411B0;
dword_1152250[3] = (int)func_hehe_sub_2_1141090;
dword_1152250[4] = (int)func_print_success;
dword_1152250[5] = (int)func_hehe_sub_3_11410f0;
dword_1152250[6] = (int)func_hehe_equ_fu3_11411B0;
dword_1152250[7] = (int)func_hehe_equ_fu1_1141120;
dword_1152250[8] = (int)do_work;
dword_1152250[9] = (int)do_work_1;
dword_1152250[10] = (int)do_work_2;
dword_1152250[11] = (int)do_work_4;
实际执行的是： dword_1152250[8]处的函数。
上OD有反调试，不用管他，直接运行，输入注册码。
然后附加。
EIP转到do_work起始地址，反复跑了几次，发现是个11*11的数组，接着把数组dump出来，再对照代码。
1.先求第四列11个数的和
2.用这个和与每一行之和比较。。。
3.用这个和与每一列之和比较。。。
4.。。。。
明白了是数独。
表格地址：0x291fA0(代码中的nnTable)
注册码是0x290ee0(代码中的xxList)这个表中的下标，从这个表中获取到对应位的值写入nnTable中值为0的位置，如果最后构成数独就成功了。
代码：
# -*- coding: cp936 -*-
#输入的注册码为下标 在这里边取值，填入nnTable中值为0的地方，如果形成11*11的数独就成功了
xxList=[0x3A, 0x5D, 0x49, 0x5F,
0x78, 0x51, 0x0F, 0x55,
0x5E, 0x12, 0x15, 0x26,
0x58, 0x47, 0x69, 0x6D,
0x3F, 0x5C, 0x56, 0x3D,
0x29, 0x04, 0x77, 0x4F,
0x52, 0x6E, 0x2C, 0x1B,
0x44, 0x1C, 0x14, 0x4C,
0x46, 0x03, 0x3B, 0x25,
0x38, 0x06, 0x7B, 0x7E,
0x0C, 0x24, 0x4E, 0x3C,
0x1E, 0x13, 0x1D, 0x53,
0x40, 0x57, 0x54, 0x6A,
0x5B, 0x31, 0x66, 0x27,
0x74, 0x32, 0x2A, 0x5A,
0x60, 0x0A, 0x02, 0x3E,
0x34, 0x08, 0x6F, 0x23,
0x7F, 0x30, 0x10, 0x07,
0x64, 0x17, 0x67, 0x05,
0x48, 0x62, 0x7A, 0x73,
0x01, 0x71, 0x1F, 0x37,
0x18, 0x70, 0x4B, 0x7C,
0x2E, 0x79, 0x2D, 0x33,
0x20, 0x28, 0x2B, 0x43,
0x22, 0x72, 0x36, 0x41,
0x11, 0x42, 0x6B, 0x61,
0x59, 0x19, 0x2F, 0x39,
0x68, 0x45, 0x0B, 0x76,
0x1A, 0x21, 0x7D, 0x80,
0x4D, 0x63, 0x50, 0x16,
0x65, 0x35, 0x6C, 0x4A,
0x0E, 0x75, 0x09, 0x0D,
0x02, 0x03, 0x04, 0x05,
0x06, 0x07, 0x08, 0x09,
0x0A, 0x0B, 0x0C, 0x0D,
0x0E, 0x0F, 0x10, 0x11,
0x12, 0x13, 0x14, 0x15,
0x16, 0x17, 0x18, 0x19,
0x1A, 0x1B, 0x1C, 0x1D,
0x1E, 0x1F, 0x20, 0x21,
0x22, 0x23, 0x24, 0x25,
0x26, 0x27, 0x28, 0x29,
0x2A, 0x2B, 0x2C, 0x2D,
0x2E, 0x2F, 0x30, 0x31,
0x32, 0x33, 0x34, 0x35,
0x36, 0x37, 0x38, 0x39,
0x3A, 0x3B, 0x3C, 0x3D,
0x3E, 0x3F, 0x40, 0x41,
0x42, 0x43, 0x44, 0x45,
0x46, 0x47, 0x48, 0x49,
0x4A, 0x4B, 0x4C, 0x4D,
0x4E, 0x4F, 0x50, 0x51,
0x52, 0x53, 0x54, 0x55,
0x56, 0x57, 0x58, 0x59,
0x5A, 0x5B, 0x5C, 0x5D,
0x5E, 0x5F, 0x60, 0x61,
0x62, 0x63, 0x64, 0x65,
0x66, 0x67, 0x68, 0x69,
0x6A, 0x6B, 0x6C, 0x6D,
0x6E, 0x6F, 0x70, 0x71,
0x72, 0x73, 0x74, 0x75,
0x76, 0x77, 0x78, 0x79,
0x7A, 0x7B, 0x7C, 0x7D,
0x7E, 0x7F, 0x80, 0x81]
def findChar(nValue):
for i,x in enumerate(xxList):
if nValue==x:
return(i,chr(i))
return (0,"")
nnTable=[0x0, 0x2D, 0x42, 0x4C, 0x56, 0x60, 0x6A, 0x74, 0x05, 0x0F, 0x19,
0x3B, 0x0, 0x4F, 0x59, 0x6E, 0x78, 0x09, 0x13, 0x1D, 0x27, 0x31,
0x53, 0x5D, 00, 0x71, 0x02, 0x0C, 0x21, 0x2B, 0x35, 0x3F, 0x49,
0x6B, 0x75, 0x06, 00, 0x1A, 0x24, 0x2E, 0x38, 0x4D, 0x57, 0x61,
0x0A, 0x14, 0x1E, 0x28, 0, 0x3C, 0x46, 0x50, 0x5A, 0x64, 0x79,
0x17, 0x2C, 0x36, 0x40, 0x4A, 0, 0x5E, 0x68, 0x72, 0x03, 0x0D,
0x2F, 0x39, 0x43, 0x58, 0x62, 0x6C, 0, 0x07, 0x11, 0x1B, 0x25,
0x47, 0x51, 0x5B, 0x65, 0x6F, 0x0B, 0x15, 0, 0x29, 0x33, 0x3D,
0x5F, 0x69, 0x73, 0x04, 0x0E, 0x18, 0x22, 0x37, 0, 0x4B, 0x55,
0x77, 0x08, 0x12, 0x1C, 0x26, 0x30, 0x3A, 0x44, 0x4E, 0, 0x6D,
0x16, 0x20, 0x2A, 0x34, 0x3E, 0x48, 0x52, 0x5C, 0x66, 0x70, 0x01]
tempList=[]
for i in range(0,11):
nSum=0
for j in xrange(0,11):
nSum=nSum+nnTable[i*11+j]
#print "%d,%02x"%(nSum,671-nSum)
tempList.append(671-nSum)
strKey=""
for x in tempList:
n,s=findChar(x)
#print "%02x %s"%(n,s)
strKey+=s
print strKey
答案：CmJF92oRcu
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