[原创]RCTF bloker_vm 侧信道爆破解法-软件逆向-看雪-安全社区|安全招聘|kanxue.com

[原创]RCTF bloker_vm 侧信道爆破解法

发表于: 2024-6-14 19:56 2552

[原创]RCTF bloker_vm 侧信道爆破解法

z2zccc

2024-6-14 19:56

2552

看了https://bbs.kanxue.com/thread-281796.htm#msg_header_h3_8 想着找题练练手QAQ
通过字符串可以找到主逻辑程序有反调试但是在主逻辑里没看着用ida attach 即可起调试

通过对比输入与最终的字符串可以确定是单字节加密

校验逻辑应该在这

尝试使用侧信道爆破

但是这里是用侧信道爆破发现结果都是相同的尝试patch二进制文件让其能够泄露一定的信息

如果校验发现不相同则直接让他跳出循环

脚本如下：

js脚本如下：

运行结果如下

的

最终flag：RCTF{a_baby_debug_blokes}

import subprocess
import frida
import sys
import win32api
import win32con
  
number = 0
flaglen = 43
filename = "bloker_vm.exe"
#                  flag{O1SC_VM_1s_h4rd_to_r3v3rs3_#a78abffaa#}
flag = bytearray(b'!'*25)
jscode = open("blockvm.js", "rb").read().decode()
new_number = 0
  
  
result = 0
def brute(F):
  
    def on_message(message, data):
        global result
        if message['type'] == 'send':
            result = message['payload']
            # print(result)
        else:
            print(message)
    process = subprocess.Popen(filename, stdin=subprocess.PIPE,
                               stdout=subprocess.PIPE,
                               stderr=subprocess.PIPE,
                               universal_newlines=True)
  
    session = frida.attach(filename)
    script = session.create_script(jscode)
    script.on('message', on_message)
    script.load()
    process.stdin.write(F.decode())
    #print(F.decode())
    output, error = process.communicate()
    #print(output,error)
  
    #print(f"number:{result}")
    process.terminate()
    return result
import time
  
count = 0
  
new_number = brute(flag)
number = new_number
t = time.time()
st = t
  
while count < flaglen:
    number = brute(flag)
    # print(flag.decode())
    if number != new_number:
        print(f"本位耗时:{time.time()-t}s,正确字符为：{chr(flag[count])}")
        t = time.time()
        print(flag.decode())
        new_number = number
        count += 1
    else:
        flag[count] += 1
        while(flag[count] > 127):
            flag[count] = 33
            count -= 1
            flag[count] += 1
print(flag.decode())
print(f"总耗时{time.time()-st}")